理论力学课后答案机械工业khda

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1、2-12-55FO2-55(a) MO (F )(b) MO (F )(c) MO (F )(d) MO (F )(e) MO (F )(f) MO (F )0FlFb Fl sinFl 2b2 sinF (lr)2-2O A B50NC2-562-56R cos 60M O50 cos 30R sin 6050 sin 3050 250 sin 306250 N m m6.25 N mM AM B2-3M OM O50 cos 3050 sin15RR6.256.2510.8253.23517.075 N m9.485 N m80N2-5317522-5751M O80(2)sin 7525

2、080sin 21.873019318.5 89420212.59.485 N mm20.21 N m30sin250sin 53.13tan0.089555.117sin(53.135.117)95.117cos 53.1325 / 3(3)902-42-58F1150 N, F2200 N, F3O2-58437.64 kN300 N, FF200 NOd12515FFF cos 45FFR xx12310310FFF cos 45FF161.64 kNR yy1231FR( Fx )2( Fy )2FR466.54 kN161.6420.27tan0.3693437.6415MM (F

3、)F cos 450.1 F0.2 16 21.44 N mOO13dMO / FR21.44 / 466.540.04596 m45.96 mm2-5F160O2 kN, F2O12-59F360 kN2-59mmFR xFR yM OFxFyF1 cos 45F1 sin 45F2F360 2 cos 4560 2 cos 454 F1 cos 456060200F2M O (F )F1 sin 452F3 360 2 cos 452420 N m602603M O1M O420 N m2-6W 5kNAC2-6ABC2-60FAFBC2FA sin 30WWFA2-73.5kNFBC5

4、kNAB10kNABWCW12-61A B2-610M BFAWW10533.513 W3W1 5F6.7 kNA5FA0Fx FBxFy06.7 kN 0FBCFBy13.5 kN2FR yFR x2-82-62F10kN q3kN/m M 8kN mA2-62Fx0FAx4qF cos 60012FF cos 604q 104037 kNAxFy0FAyF sin 60324qFF sin 601053 kNAyM AM A0M A2MF cos 60043F sin 60300M A3 kN m37.98 kN m2-92-63ACABCAB8kN100kNACAB2-6Fx FAxM

5、A04 kN0FAx8 cos 600FB12 cos 30006 cos 3052.31kN8 3 0FB5024 /(12 cos 30 ) 502.31FyFAy0FAy100FB8 sin 6052.31 54.62 kN1000432-102-64F=2kN M=2.5 kNmq 1kN/m2-64(a)12M0q200F2q 1MF 3 0ABF(M3F ) / 24 kNBFx FyFAyFAxFAyFFB0FBq 1F01kNq 13(b)q 32M A0FBy2F 11 0( 3F2) / 2FBx FA0.25 kN0By2Fx0q 32Fy0FByF0q 332FFF20

6、.253.75 kNABy22-652-11W=500kN1.5mW1=250kN10mW22-65xFA W2 (xFB03)0MB01.5W10W10(1)M A0W2 x4.5W0(2)(1)(2)10W134.5W3W2500 1500310003W33.3 kN22250x6.75 mW21000 / 32-122-66W1 60kNW2 30kN(1)W25k4m(2)2-66(1)W325kNM E0W1252.5 W38 W22FD40602.58302F72.5 kND4Fy0FDFEW1 FDEW2W30FEW1W3=0W2W3 F60302572.542.5 kN(2)M

7、 EDE02W2W1W1(DE1.5) W2201.52.5 m2 301.560W2=30kND4M D0 1.5W1W34 W1 1.5 W2(DE2)0W2(DE2)1.56030 (2.52)W56.25 kN3442-13q 20kN/mAB2-67F130kN F2 40kNM30kN m2-67(a)M OFA8FC cos 600Fx FCFyFB0F10F1 cos 6030 kNFAFC sin 60FBF1 sin 60F2q30F1 sin 60F2q 3FAFC sin 603 63.2230 sin 6030 sin 6088.74 kN402(b)M O1M0MF

8、12F2 cos 3042 s n 306FD cos 458FD sin 4540F12F2 cos 302F2 sin 306FDcos 458 sin 45466 28.42 kNM O 20MM6F14F2 cos 3020BF14F2 cos 3062FB33030 4402 263.45 kN5M D0MMFB8FB8F16FC cos 454F2 sin 3020F16F2 sin 302FC4 2 / 2130 3.45 8 30 6402 22257.41 kN2-14r 0.1mADBCABABC2-68DW1800N0.2mBD 0.4ma45A2-68M A0FBC s

9、in 45ABFT rW ( ADr)0WADWF62848.4 N00BCAB sin 453 sin 45Fx FAxFyFAy0FT0WFAxFTFBC cos 450FBC cos 45NFAyFBC01200 NFBC sin 452-15W1=50kNACDCEC2-69W2=10kNA BD2-69M FWFkNG22W2FyFF0W1FFFGW110 kN0W2FGCDM C0FD6FG10Fy0FCFD500FG65062506F8.33 kNF50F41.67 kNDCDAC6M A0FB FC36FF105FC60FF55250F100 kNB3FA31010FyFA0F

10、CFBFC010010FB41.6748.33 kN2-162-70FqMC2-70(a)CDFDFCqaqaM CFy00FDFC2aq2a2aa00FDqACFB FqaqaM AFy00FBFAaFBFCFC2a2qaq2a0a0(b)CDM C0FD2aM0FD2a MFF0FFyCDC2aACFMa2MFy00FaFF2F0M0FABCB2aFAF2MaF2M2aFFFACB2a(c)CD2 F42 F22 F4FM0F2aF sin 45a0DCDFF0FF cos 450CxxCxFF0FFF sin 450CyyCyDAC72 F22 F4FF0FF0xAxCxAxFF0FF0

11、yAyCyAy2 Fa2MMF2aMM0MMF2a0AACyACy(d)CDqa4M0F2aqaa / 20FCDDF3 qaF0FFqa0yCDC4ACFx0FAx0F7 qaF0FqaF0yAyCyAy43 a2Mqa 2M0MqaF2a0AAACy2-172-71AF1BF2F1F22-71Bx(AB)3 FF0FF cos 300FxAB2AB22Ay(F1)226 FF0FFcos 450FFy1AB1AB242-182-72OA 0.4mM2O1B0.6m M1AB1N m2-72OAM0O1B1FOA sin 30M0F5 kNAB1AB0.4sin 308M0M 2FABO1